NSString *stringURL = @"twitter://post?message=check out this cool lifestyle app http://itunes.com/apps/wayoflife";
NSString *escapedStringURL = [stringURL stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding]
NSURL *url = [NSURL URLWithString:escapedStringURL];
[[UIApplication sharedApplication] openURL:url];
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Of course it requires that the user has Twitter installed on his/her phone to handle this URL.
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